scripting.. how long to learn?

[Triggerhappy]

hey, penguinman, i'll get back to you on this, its exam week fo me, so when i get the time i'll come back and show you how to use sin cos and tan.
alright?
unless someone else would like to explain it...

[penguinman]

ok great,

 

[RedHouse]

i dont understand it that well, but i know h^2 = b^2 + a^2,


this is some text i put in one of my scripts, it shows two ways to work out 2d rotations of a point on a grid but it took me ages to figure it out and i still dont know if its right but it works so im happy. I would explain it if i could but I really can't remember how the hell it works.

Code: [Select]

_m_TO_SQUARE = (_x_ORIGEN_U ^2) + (_y_ORIGEN_U ^2)
_m = sqrt _m_TO_SQUARE
_x_ORIGEN_ROTATED_U = _x_ORIGEN_U * cos angle + _y_ORIGEN_U * sin angle
_y_ORIGEN_ROTATED_U = _y_ORIGEN_U * cos angle - _x_ORIGEN_U * sin angle
_x_ROTATED_U = _x_ORIGEN_ROTATED_U + _xT
_y_ROTATED_U = _y_ORIGEN_ROTATED_U + _yT
_x_POSITION_U = ((_x_ROTATED_U - ((sin angle) * _m)))
_y_POSITION_U = ((_y_ROTATED_U - ((cos angle) * _m)))
maybe someone smarter will make sense of it.

[THobson]

Apologies if I am missing something (this is a long thread).

Does this help:

A right angled triangle is one that has one angle = 90 degrees.  The side opposite this angle is called the hypotenuse.  Let us call it h and let us call the other sides x and y.
Also let us call the angle opposite side x theta.  The angle opposite side y will therefore be (90 - theta).

Then

h^2 = x^2 + y^2

sin (theta) = x/h
cos (theta) = y/h
tan (theta) = x/y

sin (90-theta) = y/h
cos (90-theta) = x/h
tan (90-theta) = y/x

From the above you can work out anything you need.


For example:
If an object is located at (x1,y1) with direction theta
and you want the coordinates of a point that is a distance d away  at an angle alpha to the direction the object is facing then the formulae are:

x = x1 + d*Sin(theta + alpha)
y = y1 + d*Cos(theta + alpha)



And:
To find the coordinates of a point in front of or to the side of an object

if:
x1,y1 are the coordinates of the object
theta is the direction of the object
d is the distance of the point from the object

then:
For a point in front of the object
X coordinate = x1 + d*sin(theta)
y coordinate = y1 + d*cos(theta)

(for a point behind use -d or theta+180)


For a point to the right of the object
X coordinate = x1 + d*cos(theta)
y coordinate = y1 - d*sin(theta)

(for a point to the left use -d or theta+180)  
 
 

[RedHouse]

thats very helpfull thx

[Triggerhappy]

well there you go penguinman

[Lean Bear]

TriggerHappy's right everyone.

The Pythagoras Theorem, radii of circles, algebra in general is required to be able to script efficiently in computers. Not only OFP.

That's why you'll find that at college etc. to do a decent computing course involving prgramming, scripting etc. you'll need a high grade in Math.

[dan ick]

 ;D Hey

             You will get there in the end i myself am just learning simple scripts and yes it is a bit confusing at first but like someone mentioned start with the init fields etc.....

I only started using PC's about a year and a half ago and i started with the inits,on activ etc.......
I could not understand scripts for months but i read Snypirs guide and a few others quite a few times till i could nearly remember it word for word,However i just seen the post with someone meantioning pythagoros,After seeing that very word and reading a bit of the example,There is now smoke pouring out of my ears and i can smell wood burning

Anyway Good luck


YOU CAN DO IT,YOU DA MAN ;D

[OFPfreak]

yay locked it... that should do it for completely off-topic posts... go make ure own...